![]() They refused to give the number for 20 minutes even though the serial number and challange number checked out fine by their own reckoning. Phoning for the number resulted in a half hour delay as the Indian tech and his supervisor struggled to understand how the challenge-response structure of Quark 6's system works. We recently had to keep extra freelancers until 9 pm because one of our Quarks lost its authorization after a week of being fully authorized, and could not be reinstalled/authorized. If it is after 3 pm PST, you cannot phone Quark and get a new number. It does seem impossible to uninstall Quark 6 on a Mac and get online authorization. ![]() In terms of activation, the agency I service has been seriously inconvenienced by it. RE: Quark 6 activation daanmuller (TechnicalUser) 30 Dec 03 03:57 Otherwise, keep your typing fingers still and think silently to yourself that you know more than everyone else. If you have a solution or suggestion, post it in a way that will HELP the people who read it. So, all in all, please don't feel like you HAVE to post a reply to a question just because you have a little bit of related knowledge. SUPPORT" when I had already stated that calling them did not work? Did you read my post? You didn't even offer an explanation such as "Well, when I had to reactivate my version, I called Quark and they did it for me over the phone." Maybe other people could do it that way, too if we knew more about your situation. Why would you reply "THE ONLY OPTION AFTER REINSTALLING IS CALL QUARK TECH. And to save him and others wasted time, I also looked up the email address and fax number that I personally had to use. I went through the exact scenario stevemoore asked about last week and informed him of the steps I had to go through to resolve it. It may not always be exact and there may be better ways, but we offer suggestions. "Activation is still there in the next update." Do you mean you still have to activate Quark when it's installed to get full functionality? Do you mean you still have to RE-activate it if you re-install Quark? How do you know this? Where did you hear it? Do you already have the update? How did you get it? Where should we (the people you're trying to help - since that's what this website is for) look for it? It seems to me that if you really knew this for a fact, your response would be a bit more detailed.Īt least stevemoore and I, and pretty much everyone else who has posted on this site, explain why (we think) we know what we're posting is true. Snippy half sentences aren't much help to anyone in these forums. ![]() Thanks again for taking the time to post that.This forum isn't to show off how much you know it's to share it. What is the lightest susy particle in MSSM? So a consequence of this is that the lightest SUSY particle is absolutely stable, even if it is much more massive than non-susy particles, right? Thank you for a very informative post! I have tried to understand the exact consequences of R parity by reading articles on SUSY but it has never been clear like that. Experimentalists may be getting closer to this possibility, I hope. In order to prove the existence of R-parity, we now need to find some supersymmetric particles that exhibit these kinds of transitions. All of these rules are a direct result of R-parity. But it should be pointed out that a supersymmetric particle cannot decay into two new supersymmetric particles. In all this, the standard decays which are well known in experimental physics remain allowed, such as quark transitions involving weak bosons. Similarly, a "squark" cannot decay into another "squark" and a neutralino, but can decay into a quark and a neutralino. This means, for example, that a top quark could not decay into a charm quark and a neutralino, but a top quark could decay into a charm "squark" and a neutralino. Where I have labeled "normal" (N) or standard fundamental particles and "supersymmetric" (S) fundamental particles. This means that, in order to conserve the R-parity, only the following two-body decay transitions are allowed Īlong with the following two-body scattering transitions You see, the standard fundamental particles, such as leptons, quarks, and the vector bosons all have positive R-parity, while the supersymmetric partners, such as sleptons, squarks, neutralinos and charginos have negative R-parity. R-parity is useful in the supersymmetric model of fundamental particles. Why there is a need for a new type of parity? is cpt voilated in supersymmetry
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